What the likelihood of this dice roll?
So there is a dice game at the pub in which you enjoy 8 six-sided dies and have 1 roll to get the following roll (6,6,5,5,5,3,2,1). That is 2 sixes, 3 fives, a three, a two, an a one. I have be trying to calculate the odds. I want to say it would be roughly a factorial (6x6x6x5x4x3x2x1 = 25920 to 1 odds). Can anyone confirm that I did that right?
Answers:
It is 108/6^8 or one in 15,552
Odds on a single 6 sided die are 1 in 6.
Odds on two 6 sided die are 1 in 36, or 6 squared.
6 cubed would be likelihood on 3 die...
so 8 die would be 6 to the 8th.
Your odds of getting 8 dice out of 8 dice perfectly in an exact writ would be 1 in 1,679,616 or 6 raised to the 8th power.
However, you don't need the dice to be within the exact order. You just need in that to be 2 6's, 3 5's, a 3, a 2, and a 1 in ANY order. Folks that are saying the answer is 6 raise to the 8th power are wrong.
What you need to figure out, is how many ways 66555321 can be mixed up. Once you find out how frequent combinations of that number there are, divide that into 1,679,616 for your answer.
My brain isn't working well enough to numeral out how many combinations there are in an 8-digit number when 1 number is repeated once (the 6) and another number is repeated twice (the 5).
The just thing I'm fairly sure about right in a minute is that your calculation is NOT correct. The only thing I'm 100% sure of is that clich¨¦ 6 raised to the 8th power is WRONG.
confirmed! Source(s): math mo tician
(1/6)^8
the chance of getting any specific number is 1/6, and that chance is taken eight times
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Answers:
It is 108/6^8 or one in 15,552
Odds on a single 6 sided die are 1 in 6.
Odds on two 6 sided die are 1 in 36, or 6 squared.
6 cubed would be likelihood on 3 die...
so 8 die would be 6 to the 8th.
Your odds of getting 8 dice out of 8 dice perfectly in an exact writ would be 1 in 1,679,616 or 6 raised to the 8th power.
However, you don't need the dice to be within the exact order. You just need in that to be 2 6's, 3 5's, a 3, a 2, and a 1 in ANY order. Folks that are saying the answer is 6 raise to the 8th power are wrong.
What you need to figure out, is how many ways 66555321 can be mixed up. Once you find out how frequent combinations of that number there are, divide that into 1,679,616 for your answer.
My brain isn't working well enough to numeral out how many combinations there are in an 8-digit number when 1 number is repeated once (the 6) and another number is repeated twice (the 5).
The just thing I'm fairly sure about right in a minute is that your calculation is NOT correct. The only thing I'm 100% sure of is that clich¨¦ 6 raised to the 8th power is WRONG.
confirmed! Source(s): math mo tician
(1/6)^8
the chance of getting any specific number is 1/6, and that chance is taken eight times
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if i use an e check to deposit on full tilt poker what will happen. how will it show up in my bank statement? the idea I ask is because I dont want my parents to find out about this. Will I get something in the correspondence from full...
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A ticket purchaser, basing his selection on family members' pool. A ticket purchaser, base his selection on family members' birthdates, thus restricted his possible winning combinations to numbers 1 through 31. Did he terminate his chances of winning by his eliminating numbers 32 through 40...
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